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Perl Cookbook

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Previous: 4.4. Doing Something with Every Element in a ListChapter 4
Arrays
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4.5. Iterating Over an Array by Reference

Problem

You have a reference to an array, and you want to use foreach to work with the array's elements.

Solution

Use foreach or for to loop over the dereferenced array:

# iterate over elements of array in $ARRAYREF
foreach $item (@$ARRAYREF) {
    # do something with $item
}

for ($i = 0; $i <= $#$ARRAYREF; $i++) {
    # do something with $ARRAYREF->[$i]
}

Discussion

The solutions assume you have a scalar variable containing the array reference. This lets you do things like this:

@fruits = ( "Apple", "Blackberry" );
$fruit_ref = \@fruits;
foreach $fruit (@$fruit_ref) {
    print "$fruit tastes good in a pie.\n";
}
Apple tastes good in a pie.
Blackberry tastes good in a pie.

We could have rewritten the foreach loop as a for loop like this:

for ($i=0; $i <= $#$fruit_ref; $i++) {
    print "$fruit_ref->[$i] tastes good in a pie.\n";
}

Frequently, though, the array reference is the result of a more complex expression. You need to use the @{ EXPR } notation to turn the result of the expression back into an array:

$namelist{felines} = \@rogue_cats;
foreach $cat ( @{ $namelist{felines} } ) {
    print "$cat purrs hypnotically..\n";
}
print "--More--\nYou are controlled.\n";

Again, we can replace the foreach with a for loop:

for ($i=0; $i <= $#{ $namelist{felines} }; $i++) {
    print "$namelist{felines}[$i] purrs hypnotically.\n";
}

See Also

perlref (1) and perllol (1); Chapter 4 of Programming Perl; Recipe 11.1; Recipe 4.4


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